document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27390>Question 27390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive integers such that the sum of three times the first integer, one-third of the second integer, and eight times the third integer is -29. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14888 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 1st integer be \"x\"<BR>\n" );
document.write( "2nd is \"x+1\"<BR>\n" );
document.write( "3rd is \"x+2\"<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "3x+(1/3)(x+1)+8(x+2)=-29<BR>\n" );
document.write( "Multiply through be \"3\" to get:<BR>\n" );
document.write( "9x+(x+1)+24(x+2)=-87<BR>\n" );
document.write( "9x+x+1+24x+48=-87<BR>\n" );
document.write( "34x=-136<BR>\n" );
document.write( "x=-4<BR>\n" );
document.write( "x+1=-3<BR>\n" );
document.write( "x+2=-2<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );