document.write( "Question 198327: Quadratic Equations
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document.write( "3. The length of a rectangle is 16cm greater than its width. The area is 35m^2. Find the dimensions of the rectangle, to the nearest hundredth of a metre.
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Algebra.Com's Answer #148825 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! Area = Length * Width \n" ); document.write( ". \n" ); document.write( "A = ( w+16) * ( w) \n" ); document.write( ". \n" ); document.write( "35 = w^2 + 16w \n" ); document.write( ". \n" ); document.write( "0 = w^2 +16w -35 \n" ); document.write( ". \n" ); document.write( "using quadratic equation \n" ); document.write( ". \n" ); document.write( "a = 1,,b = 16,,,c=-35 \n" ); document.write( ". \n" ); document.write( "w = { - (16) +/- sq rt ( (16)^2 - 4 (1) (-35) } / 2 (1) \n" ); document.write( ". \n" ); document.write( "w = { -16 +/- 19.899 } /2 \n" ); document.write( ". \n" ); document.write( "w = -17.949, + 1.949,,,,-17.95, +1.95 ,,,,,neg dim not reasonable therefore w= 1.95 \n" ); document.write( ". \n" ); document.write( "L = w+16 = 17.95 \n" ); document.write( ". \n" ); document.write( "checking \n" ); document.write( "(-17.95) (-17.95 +16 ) = 35,,,ok \n" ); document.write( ". \n" ); document.write( "(1.95) ( 1.95 + 16 ) = 35,,,,ok \n" ); document.write( ". \n" ); document.write( "A = 1.95 * 17.95 = 35,,,,ok \n" ); document.write( " |