document.write( "Question 198272: solve
\n" ); document.write( "log4(4b+14)-log4(b^2-3b-17)=1/2
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Algebra.Com's Answer #148809 by edjones(8007)\"\" \"About 
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log4(4b+14)-log4(b^2-3b-17)=1/2
\n" ); document.write( "log[4]((4b+14)/(b^2-3b-17))=1/2
\n" ); document.write( "4^log[4]((4b+14)/(b^2-3b-17))=4^(1/2)
\n" ); document.write( "(4b+14)/(b^2-3b-17)=2
\n" ); document.write( "4b+14=2b^2-6b-34
\n" ); document.write( "2b^2-10b-48=0
\n" ); document.write( "b^2-5b-24=0
\n" ); document.write( "(b-8)(b+3)=0
\n" ); document.write( "b=8, b=-3
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\n" ); document.write( "Ed
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