document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198274>Question 198274</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve <BR>\n" );
document.write( "LN(x^2+10)>LNx+LN7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148807 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln(x^2+10)>ln(x)+ln(7)<BR>\n" );
document.write( "e^ln(x^2+10)>e^ln(7x)<BR>\n" );
document.write( "x^2+10>7x<BR>\n" );
document.write( "x^2-7x+10=0 Use an equal sign instead of inequality.<BR>\n" );
document.write( "(x-5)(x-2)=0<BR>\n" );
document.write( "x=5, x=2 These are inflection points.<BR>\n" );
document.write( "Since the coefficient of x^2 is positive (+1) the graph has a minimum and the equation is negative when 5>x>2<BR>\n" );
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document.write( "Ed<BR>\n" );
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