document.write( "Question 198333: Quadratic equation
\n" ); document.write( "6. The length of one leg of a right triangle is 7 cm more than that of the other leg. The length of the hypotenuse is 3 cm more than double that of the shorter leg. Find the lengths of each of the three sides.
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Algebra.Com's Answer #148802 by stanbon(75887)\"\" \"About 
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The length of one leg of a right triangle is 7 cm more than that of the other leg. The length of the hypotenuse is 3 cm more than double that of the shorter leg. Find the lengths of each of the three sides.
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\n" ); document.write( "shorter leg : x
\n" ); document.write( "longer leg : x+7
\n" ); document.write( "hypotenuse: 2x +3
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\n" ); document.write( "Equation:
\n" ); document.write( "leg^2 + leg^2 = hypotenuse^2
\n" ); document.write( "x^2 + (x+7)^2 = (2x+3)^2
\n" ); document.write( "x^2 + x^2 + 14x + 49 = 4x^2 + 12x + 9
\n" ); document.write( "2x^2 -2x - 40 = 0\r
\n" ); document.write( "\n" ); document.write( "x^2 - x - 20 = 0
\n" ); document.write( "(x-5)(x+4) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 5 (shorter leg)
\n" ); document.write( "x+7 = 12 (longer leg)
\n" ); document.write( "2x+3 = 13 (hypotenuse)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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