document.write( "Question 198342: How much 151 Rum, which is 75.5% alcohol needs to be mixed with Rum 80, which is 40% alcohol to obtain a 1000ml 65% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #148795 by stanbon(75887)\"\" \"About 
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How much 151 Rum, which is 75.5% alcohol needs to be mixed with Rum 80, which is 40% alcohol to obtain a 1000ml 65% alcohol solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.755x + 0.40(1000-x) = 0.65(1000)
\n" ); document.write( "Multiply thru by 1000
\n" ); document.write( "755x + 400*1000-400x = 650*1000
\n" ); document.write( "355x = 250000
\n" ); document.write( "x = 704.23 ml (amt. of 75.5% alcohol in the mixture)
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\n" ); document.write( "1000-x = 285.77 ml (amt. of 40% alcohol in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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