document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198226>Question 198226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Parkhursts used 160 yd of fencing to enclose a rectangular corral and to divide it into two parts by a fence parallel to one of the shorter sides. Find the dimensions of the corral if its area is 1000 yd^2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148789 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The Parkhursts used 160 yd of fencing to enclose a rectangular corral and to<BR>\n" );
document.write( " divide it into two parts by a fence parallel to one of the shorter sides.<BR>\n" );
document.write( " Find the dimensions of the corral if its area is 1000 yd^2.<BR>\n" );
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document.write( "Let x = the width, the shorter side<BR>\n" );
document.write( "Let L = the length<BR>\n" );
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document.write( "Perimeter for this configuration <BR>\n" );
document.write( "2L + 3x = 160<BR>\n" );
document.write( "L in terms of x<BR>\n" );
document.write( "2L = 160 - 3x<BR>\n" );
document.write( "divide both sides by 2<BR>\n" );
document.write( "L = 80 - 1.5x<BR>\n" );
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document.write( "Area:<BR>\n" );
document.write( "L * x = 1000<BR>\n" );
document.write( "substitute (80-1.5x) for L<BR>\n" );
document.write( "(80-1.5x) * x = 1000<BR>\n" );
document.write( "A quadratic equation:<BR>\n" );
document.write( "-1.5x^2 + 80x - 1000 = 0<BR>\n" );
document.write( "Multiply by -2, change the signs, get rid of the decimal<BR>\n" );
document.write( "3x^2 - 160x + 2000 = 0<BR>\n" );
document.write( "Factors to:<BR>\n" );
document.write( "(3x - 100)(x - 20) = 0<BR>\n" );
document.write( "Two solutions<BR>\n" );
document.write( "3x = 100<BR>\n" );
document.write( "x = 33<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and<BR>\n" );
document.write( "x = 20 yd wide is the reasonable solution<BR>\n" );
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document.write( "Find the length<BR>\n" );
document.write( "L = 80 - 1.5(20)<BR>\n" );
document.write( "L = 80 - 30<BR>\n" );
document.write( "L = 50 yds long<BR>\n" );
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document.write( "Check solution<BR>\n" );
document.write( "2(50) + 3(20) = 160<BR>\n" );
document.write( "and<BR>\n" );
document.write( "50 * 20 = 1000 sq/yds </SPAN>\n" );
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