document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198314>Question 198314</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The tangent of p is -1/radical 3 and the secant of p is -2/ radical 3. What is the sine of p? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148784 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The tangent of p is -1/radical 3 and the secant of p is -2/ radical 3. What is the sine of p?<BR>\n" );
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document.write( "tan(p) = -1/sqrt(3) = y/x <BR>\n" );
document.write( "sec(p) = -2/sqrt(3) = r/x implies r = 2 and x = -sqrt(3)<BR>\n" );
document.write( "y = sqrt(r^2-x^2) = sqrt[4 - 3] = 1<BR>\n" );
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document.write( "If tan is negative and sec is neg, p must be in the 2nd quadrant<BR>\n" );
document.write( "where sin is positive.<BR>\n" );
document.write( "sin(P) = y/r = 1/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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