document.write( "Question 198242This question is from textbook
\n" );
document.write( ": Walt made an extra $9000 last year from a part-time job. He invested part of the money at a 9% annual rate of interest, and the rest at an 8% annual rate of interest. At the end of the year, he made a total of $770 in interest. How much was invested at 8%? \n" );
document.write( "
Algebra.Com's Answer #148763 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .08x+.09(9,000-x)=770 \n" ); document.write( ".08x+810-.09x=770 \n" ); document.write( "-.01x=770-810 \n" ); document.write( ".01x=-40 \n" ); document.write( "x=-40/-.01 \n" ); document.write( "x=$4,000 amount invested @ 8%. \n" ); document.write( "9,000-4,000=5,000 amount invested @ 9%. \n" ); document.write( "Proof: \n" ); document.write( ".08*4,000+.09*5,000=770 \n" ); document.write( "320+450=770 \n" ); document.write( "770=770 \n" ); document.write( " |