document.write( "Question 198242This question is from textbook
\n" ); document.write( ": Walt made an extra $9000 last year from a part-time job. He invested part of the money at a 9% annual rate of interest, and the rest at an 8% annual rate of interest. At the end of the year, he made a total of $770 in interest. How much was invested at 8%? \n" ); document.write( "
Algebra.Com's Answer #148763 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
.08x+.09(9,000-x)=770
\n" ); document.write( ".08x+810-.09x=770
\n" ); document.write( "-.01x=770-810
\n" ); document.write( ".01x=-40
\n" ); document.write( "x=-40/-.01
\n" ); document.write( "x=$4,000 amount invested @ 8%.
\n" ); document.write( "9,000-4,000=5,000 amount invested @ 9%.
\n" ); document.write( "Proof:
\n" ); document.write( ".08*4,000+.09*5,000=770
\n" ); document.write( "320+450=770
\n" ); document.write( "770=770
\n" ); document.write( "
\n" );