document.write( "Question 198298This question is from textbook Intermediate Algebra An Applied Approach
\n" ); document.write( ": Two investments earn an annula income of $575. One investment earns an annual simple interest rate of 8.5% and the other investment earns an annual simple interest rate of 6.4%. The total amount invested is $8000. How much is invested in each account? \n" ); document.write( "
Algebra.Com's Answer #148759 by checkley77(12844)\"\" \"About 
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.085x+.064(8,000-x)=575
\n" ); document.write( ".085x+512-.064x=575
\n" ); document.write( ".021x=575-512
\n" ); document.write( ".021x=63
\n" ); document.write( "x=63/.021
\n" ); document.write( "x=3,000 ans. amount invested @ 8.5%
\n" ); document.write( "8,000-3,000=5,000 ans.amount invested @ 6.4%
\n" ); document.write( "Proof:
\n" ); document.write( ".085*3,000+.064*5,000=575
\n" ); document.write( "255+320=575
\n" ); document.write( "575=575
\n" ); document.write( "
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