document.write( "Question 198300This question is from textbook Intermediate Algebra An Applied Approach
\n" ); document.write( ": A chemist has two alloys, one of which is 10% gold and 15% lead, and the other of which is 30% gold and 40% lead. How many grams of each of the two alloys should be used to make an alloy that contains 60g of gold and 88g of lead? \n" ); document.write( "
Algebra.Com's Answer #148755 by arallie(162)\"\" \"About 
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Make an algebra problem
\n" ); document.write( "\".10a%2B.30b=60\"
\n" ); document.write( "\".15a%2B.40b=88\"\r
\n" ); document.write( "\n" ); document.write( "Solve for a variable and substitute
\n" ); document.write( "\".10a%2B.30b=60\"--->\"a=600-3b\"
\n" ); document.write( "\".15%28600-3b%29%2B.40b=88\"
\n" ); document.write( "\"90-.45b%2B.40b=88\"
\n" ); document.write( "\"2=.05b\"
\n" ); document.write( "\"b=40\"\r
\n" ); document.write( "\n" ); document.write( "Substitute
\n" ); document.write( "\".15a%2B.40%2840%29=88\"
\n" ); document.write( "\".15a%2B16=88\"
\n" ); document.write( "\".15a=72\"
\n" ); document.write( "\"a=480\"\r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "\".10%28480%29%2B.30%2840%29=60\"
\n" ); document.write( "\"48%2B12=60\"
\n" ); document.write( "\"60\"\r
\n" ); document.write( "\n" ); document.write( "grams of each of the two alloys should be used to make an alloy that contains 60g of gold and 88g of lead
\n" ); document.write( "480g of 10/15
\n" ); document.write( "40g of 30/40
\n" ); document.write( "
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