document.write( "Question 198253: respected sir,\r
\n" ); document.write( "\n" ); document.write( "1] A student first reduced a certain number by 20% and then increased it again by 20%. If the difference between the last number and the original number was 8, then the original number was:\r
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\n" ); document.write( "\n" ); document.write( "plz help me to solve this % sum...\r
\n" ); document.write( "\n" ); document.write( "thank u...
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Algebra.Com's Answer #148727 by arallie(162)\"\" \"About 
You can put this solution on YOUR website!
I change the 20% into 80%,when reducing, because it makes it easier to work with.
\n" ); document.write( "ie\"%28x-.2x%29=%281-.2%29x=.8x\"\r
\n" ); document.write( "\n" ); document.write( "A student first reduced a certain number (henseforth called x) by 20%...
\n" ); document.write( "\".8x\"
\n" ); document.write( "...and then increased it again by 20%.
\n" ); document.write( "\"1.2%28.8x%29\"
\n" ); document.write( "If the difference between the last number and the original number was 8...
\n" ); document.write( "\"1.2%28.8x%29-.8x=8\"
\n" ); document.write( "\".96x-.8x=8\"
\n" ); document.write( "\".16x=8\"
\n" ); document.write( "\"x=50\"
\n" ); document.write( "...then the original number was:
\n" ); document.write( "\"50\"
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