document.write( "Question 198266This question is from textbook algebra sturcture and method
\n" ); document.write( ": can you please help me determine how many x-intercepts the parabola has and wether its vertex lies above or below or on the x-axis ((( y=x^2-5x+6 )))\r
\n" ); document.write( "\n" ); document.write( " $\"y=x%5E2-5x%2B6\"$ ------(1)
\n" ); document.write( "x intercept ==> y=0. So put y=0 in (1)
\n" ); document.write( "==> $\"x%5E2-5x%2B6=0\"$
\n" ); document.write( "==> $\"%28x-3%29%28x-2%29=0\"$
\n" ); document.write( "==> x={2,3}
\n" ); document.write( "So the parabola have two x intercepts.
\n" ); document.write( "Since the sign of x^2 is positive, the parabola has a minimum at its vertex.
\n" ); document.write( "Vertex is [-b/2a,f(-b/2a)]= (5/2,-1/4) So the vertex lies below the x axis. \n" ); document.write( "

Algebra.Com's Answer #148714 by mathsteacher(28) $\"\"$ $\"About$

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