document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26650>Question 26650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1) Identify the fifth term in the sequence in which a^2=40 and r=1/2<BR>\n" );
document.write( "2) Find the sum of the geometric series in which a^1=125,r=2/5, and n=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14871 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) Identify the fifth term in the sequence in which a^2=40 and r=1/2<BR>\n" );
document.write( "TN=A*R^(N-1)<BR>\n" );
document.write( "T5=A*R^(5-1)=A*R^4=SQRT(40)*(1/2)^4=SQRT(40)/16=2SQRT(10)/16=SQRT(10)/8=0.3953\r<BR>\n" );
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document.write( "2) Find the sum of the geometric series in which a^1=125,r=2/5, and n=4<BR>\n" );
document.write( "sn=a*(1-r^n)/(1-r)<BR>\n" );
document.write( "S4=125*(1-(2/5)^4)/(1-(2/5))=203\r<BR>\n" );
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