document.write( "Question 198168: A bacteria population starts at 2032 and decrease by 15% everyday. \r
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document.write( "Write a function representing the number of bacteria present each day. \r
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document.write( "After how many days will there be fewer than 321 bacteria?\r
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document.write( "I need some help on this problem please. \r
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document.write( "Thank you in advance. \n" );
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Algebra.Com's Answer #148635 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A bacteria population starts at 2032 and decrease by 15% everyday. \n" ); document.write( "Write a function representing the number of bacteria present each day. \n" ); document.write( "f(t) = 2032(1-.15)^t \n" ); document.write( "f(t) = 2032*.85^t \n" ); document.write( ": \n" ); document.write( "After how many days will there be fewer than 321 bacteria? \n" ); document.write( "2032*.85^t = 321 \n" ); document.write( ".85^t = \n" ); document.write( ".85t = .1578 \n" ); document.write( "t*log(.85) = log(.1578) \n" ); document.write( "-.07058t = -.80189 \n" ); document.write( "t \n" ); document.write( "t = 11.36 days \n" ); document.write( "We can say after 12 days there will be less than 321 \n" ); document.write( ": \n" ); document.write( "Check solution on calc: enter 2032*.85^12 = 289 left which is less than 321 \n" ); document.write( "in 11 days: 2032*.85^11 = 340, more than 321 \n" ); document.write( " |