document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27211>Question 27211</A>: <I><SPAN STYLE=\"word-break: break-all;\">  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14861 by </B><A HREF=/tutors/aboutme.mpl?userid=shafkat_alam><B>shafkat_alam(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shafkat_alam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14861\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the point (-2,Y) is a solution fo rthe equation 3x - 2y= -18, what is the value of Y?\r<BR>\n" );
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document.write( "So, the value of x in the given equation is -2.  Putting the value in the equation we get, \r<BR>\n" );
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document.write( "    3(-2) - 2y = -18,<BR>\n" );
document.write( "or, -6 -2y + 6 = -18 + 6,<BR>\n" );
document.write( "or, -2y = -12,<BR>\n" );
document.write( "or, -2y / -2 = -12 / -2,<BR>\n" );
document.write( "so, y = -6. (answer) </SPAN>\n" );
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