document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198154>Question 198154</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The value of a certain car decreases at the rate of 300 dollars each month after being purchased new.  Suppose that the car is worth 17,000 when it is 2 years old.     <BR>\n" );
document.write( "         a.  Determine a linear function on the axes provided.  Label appropiately  \r<BR>\n" );
document.write( "\n" );
document.write( "        c.  Use this model to determine the value of the car after 4 years.  \r<BR>\n" );
document.write( "\n" );
document.write( "        d.  Determine how long after purchase the car's value will be half of its selling price. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148607 by </B><A HREF=/tutors/aboutme.mpl?userid=arallie><B>arallie(162)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=arallie><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+0%2C+50%2C+0%2C+25000%2C+-300x%2B24200%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+0%2C+50%2C+0%2C+25000%2C+-300x%2B24200%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "y=-300x+24200\r<BR>\n" );
document.write( "\n" );
document.write( "\"y\"= value of car at month \"x\"<BR>\n" );
document.write( "\"x\"= months after purchase\r<BR>\n" );
document.write( "\n" );
document.write( "ie:\r<BR>\n" );
document.write( "\n" );
document.write( "The value of a certain car decreases at the rate of 300 dollars each month after being purchased new. Suppose that the car is worth 17,000 when it is 2 years old. \r<BR>\n" );
document.write( "\n" );
document.write( "17000=? -300(24)+24200<BR>\n" );
document.write( "17000=? -7200+24200<BR>\n" );
document.write( "17000=  17000 \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Determine the value of the car after 4 years.  \r<BR>\n" );
document.write( "\n" );
document.write( "y=-300(48)+24200<BR>\n" );
document.write( "y=-14400+24200<BR>\n" );
document.write( "y=9800\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Determine how long after purchase the car's value will be half of its selling price.\r<BR>\n" );
document.write( "\n" );
document.write( "By changing the formula slightly we can determine the answer easily.<BR>\n" );
document.write( "We will already know the final answer, half of the original value 12100.\r<BR>\n" );
document.write( "\n" );
document.write( "12100=-300x+24200<BR>\n" );
document.write( "-12100=-300x<BR>\n" );
document.write( "40 1/3=x\r<BR>\n" );
document.write( "\n" );
document.write( "3 years, 4 months, 10 days approx. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );