document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27372>Question 27372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given cos theta = 24/25 and (0 < x < pi/2)<BR>\n" );
document.write( "Evalutate: (a) sin theta (b) sec theta </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14860 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given cos theta = 24/25 and (0 < x < pi/2)<BR>\n" );
document.write( "Evalutate: (a) sin theta (b) sec theta<BR>\n" );
document.write( "since theta the angle is less than pi/2,we can think of a triangle ABC with angleABC=90 degrees or pi/2..and angle ACB =theta...so AC=hypotenuse..AB=opposite side and BC=adjacent side..so we have <BR>\n" );
document.write( "cos theta=cos C =BC/AC=24/25<BR>\n" );
document.write( "so BC=24 and AC =25...so from pythogarus theorem AB^2=AC^2-BC^2=25^2-24^2<BR>\n" );
document.write( "=(25+24)(25-24)=49...so.....AB=7<BR>\n" );
document.write( "now...sin theta = sin C = AB/AC=7/25<BR>\n" );
document.write( "sec theta = sec C = AC/BC=25/24<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );