document.write( "Question 198139: This is a problem from the Jubilee Academy's online homeschooling website, which I am enrolled in.\r
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document.write( "A freight train leaves a station traveling a constant speed of 30 miles per hour (mph). A passenger train leaves at the same time and travels in the same direction at a constant speed of 35 mph. In how many hours will the trains be 15 miles apart?\r
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document.write( "I would be able to do this problem easily if i knew how to set up the equation, which is for me the hardest part, but there were no similar solvers in the travel and distance section. Thank you. \n" );
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Algebra.Com's Answer #148597 by RAY100(1637) ![]() You can put this solution on YOUR website! Remember that x = Vt,,, where x is distance, V is velocity, and t is time \n" ); document.write( ". \n" ); document.write( "delta x = V2t2 - V1t1 \n" ); document.write( ". \n" ); document.write( "but t1 = t2 \n" ); document.write( ". \n" ); document.write( "delta x = (v2-v1) t \n" ); document.write( ". \n" ); document.write( "15 mi = ( 35 -30 ) mph * t \n" ); document.write( ". \n" ); document.write( "15 = 5 t \n" ); document.write( ". \n" ); document.write( "t=3 hrs \n" ); document.write( ". \n" ); document.write( "check \n" ); document.write( ". \n" ); document.write( "V2 = 35 *3 = 105 miles \n" ); document.write( ". \n" ); document.write( "V1 = 30 * 3 = 90 \n" ); document.write( ". \n" ); document.write( "v2 -v1 =15 ok \n" ); document.write( " |