document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198092>Question 198092</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve -5/3v+4/3=4/7-5/7 ? And can you explain it? thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148583 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve (-5/3)v + (4/3) = (4/7) - (5/7)<BR>\n" );
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document.write( "The least common multiple of the denominators is 21<BR>\n" );
document.write( "Multiply thru by 21 to get:<BR>\n" );
document.write( "-35v + 28 = 12 - 15<BR>\n" );
document.write( "-35v = -3-38<BR>\n" );
document.write( "-35v = -41<BR>\n" );
document.write( "v = 41/35<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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