document.write( "Question 163599: ok. i've got a tough one.\r
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document.write( "A man selling fruit has only three weights, but with them he can weigh any whole number of kilograms from 1 kg up to 13 kg inclusive on his balance. what weights does he have?\r
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document.write( "please HELP!!! \n" );
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Algebra.Com's Answer #148565 by J2R2R(94)![]() ![]() You can put this solution on YOUR website! The easiest way to look at this instinctively is to realise that you don’t just ‘add’ weights to weigh; you can ‘subtract’ weights by placing them on the other side.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you could only add weights you could have to use 1, 2, 4, etc. as in binary which can represent any integer using 0s and 1s. 1, 1+0, 1+1, 1+0+0, 1+0+1, 1+1+0, 1+1+1 etc. as we are adding all the time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Number, add = 2 degrees of freedom.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "But as you can also subtract (putting weights on the other side), you can use the powers of 3 instead of 2 which gives us 1, 3 and 9 to make 13. Subtracting gives us an extra degree of freedom so we can advance in powers of 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Number, add, subtract = 3 degrees of freedom\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1, 3-1, 3, 3+1, 9-3-1, 9-3, 9-3+1, 9-1, 9, 9+1, 9+3-1, 9+3, 9+3+1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, how do we subtract a weight – easy, just put it on the side of the item you are weighing.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "E.g. to weigh something of 6 kg, you would place 9 kg on one side and 3 kg on the side with the object you are trying to weigh. When they balance you know the object you are weighing is 6 kg.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the answer is 1 kg, 3 kg and 9 kg. \n" ); document.write( " |