document.write( "Question 198040: I need to find the sum or difference with unlike denominators\r
\n" ); document.write( "\n" ); document.write( "1. (y+2)/ (y^2+5y+6) + (2-y)/(y^2+y-6)
\n" ); document.write( "I did (y+2)/(y+3)(y+2) + (2-y) /(y+3)(y-2)
\n" ); document.write( "I crossed out the y+2 and the y-2 and then left with 1/(y+3)(y+3) = 1/2y+6\r
\n" ); document.write( "\n" ); document.write( "2. (1)/(X) + (7)/(3x)
\n" ); document.write( "I times 1/x by 3/3 and got 1/x.3/3 + 7/3x.1/1 = 10/6x^2\r
\n" ); document.write( "\n" ); document.write( "Please help....I'm very confused
\n" ); document.write( "Thanks,
\n" ); document.write( "JC
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Algebra.Com's Answer #148514 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Once you have determined a common denominator, adding fractions is simply the sum of the numerators over that common denominator.\r
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\n" ); document.write( "\n" ); document.write( "So far, so good. But realize that , so:\r
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\n" ); document.write( "\n" ); document.write( "Now just add the numerators -- do not add the denominators\r
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\n" ); document.write( "\n" ); document.write( "You started with the correct strategy, i.e. you multiplied the left hand fraction by 3 over 3, but then you again added the denominators when you were adding the fractions. Your result should have been:\r
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\n" ); document.write( "\n" ); document.write( "And, by the way, you also made an error when you added the denominators:\r
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\n" ); document.write( "\n" ); document.write( " rather \r
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\n" ); document.write( "\n" ); document.write( "Remember adding fractions in elementary school:\r
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