document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=198040>Question 198040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to find the sum or difference with unlike denominators\r<BR>\n" );
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document.write( "1.  (y+2)/ (y^2+5y+6) + (2-y)/(y^2+y-6)<BR>\n" );
document.write( "I did (y+2)/(y+3)(y+2) + (2-y) /(y+3)(y-2)<BR>\n" );
document.write( "I crossed out the y+2 and the y-2 and then left with 1/(y+3)(y+3) = 1/2y+6\r<BR>\n" );
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document.write( "2.  (1)/(X) + (7)/(3x)<BR>\n" );
document.write( "I times 1/x by 3/3 and got 1/x.3/3 + 7/3x.1/1 = 10/6x^2\r<BR>\n" );
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document.write( "Please help....I'm very confused<BR>\n" );
document.write( "Thanks,<BR>\n" );
document.write( "JC </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148513 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  (y+2)/ (y^2+5y+6) + (2-y)/(y^2+y-6)\r<BR>\n" );
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document.write( " (y+2)/((y+3)(y+2)) + (2-y)/((y+3)(y-2)) \r<BR>\n" );
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document.write( " (y+2)/((y+3)(y+2)) - (y-2)/((y+3)(y-2)) \r<BR>\n" );
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document.write( "1/(y+3) - 1/(y+3)\r<BR>\n" );
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document.write( "0\r<BR>\n" );
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document.write( "Ans:  (y+2)/ (y^2+5y+6) + (2-y)/(y^2+y-6) = 0\r<BR>\n" );
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document.write( "1/x+7/(3x)\r<BR>\n" );
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document.write( "3/(3x)+7/(3x)\r<BR>\n" );
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document.write( "(3+7)/(3x)\r<BR>\n" );
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document.write( "10/(3x)\r<BR>\n" );
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document.write( "Ans: 1/x+7/(3x) = 10/(3x) </SPAN>\n" );
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