document.write( "Question 198017This question is from textbook Intregrated arithmetic and basic algebra
\n" ); document.write( ": can't figure out how to solve problems like 2x+6y=12 finding three ordered pairs, I don't know where to begin \n" ); document.write( "
Algebra.Com's Answer #148504 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "What you want to find are three ordered pairs so that when you replace and in the equation with the values from the ordered pair, you have a true statement.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Pick a value for . It can be any real number, so pick a small integer -- it makes the arithmetic easier. Zero is a nice round number (so to speak), so let's pick zero for our first try.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Substitute the selected number into the equation in place of the .\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Solve for :\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Create your ordered pair from the selected value of and the calculated value of \r
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\n" ); document.write( "\n" ); document.write( "Step 5. Check your work:\r
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\n" ); document.write( "\n" ); document.write( " Checks.\r
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\n" ); document.write( "\n" ); document.write( "Perform steps 1 through 5 twice more using a new value for each time. Done.\r
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