document.write( "Question 198016: I have to construct a figure that can hold 100 mm cubed of water. I can't figure out how to find the easiest measurements to construct this. I am doing a cone so the formula is V=1/3*pi*radius squared*height. Please help! thanx! \n" ); document.write( "

Algebra.Com's Answer #148496 by josmiceli(19441) $\"\"$ $\"About$

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To get a volume of 100 mm2, suppose I have a
\n" ); document.write( "box that is 10 mm high. Now suppose it has a square base
\n" ); document.write( "The area of this square base has to be $\"10\"$ mm2
\n" ); document.write( "That means each side has to be $\"sqrt%2810%29\"$ since
\n" ); document.write( " $\"sqrt%2810%29%2Asqrt%2810%29+=+10\"$
\n" ); document.write( "To get the volume,
\n" ); document.write( " $\"sqrt%2810%29%2Asqrt%2810%29%2A10+=+100\"$ mm3
\n" ); document.write( "Now the question is, How do I construct a side $\"sqrt%2810%29\"$ mm
\n" ); document.write( "long? I know that a right triangle, with sides = $\"1\"$ and $\"3\"$ .
\n" ); document.write( "The diagonal is $\"sqrt%281%5E2+%2B+3%5E2%29\"$ , which equals
\n" ); document.write( " $\"sqrt%2810%29\"$ . Use that diagonal to make the sides of the base.
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