document.write( "Question 197945This question is from textbook beginning and intermediate algebra
\n" ); document.write( ": find three consecutive odd integers such that 3 times the sum of all three is 18 more than the product of the first and second integers \n" ); document.write( "
Algebra.Com's Answer #148475 by ankor@dixie-net.com(22740)\"\" \"About 
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find three consecutive odd integers such that 3 times the sum of all three is 18
\n" ); document.write( " more than the product of the first and second integers
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\n" ); document.write( "\"three consecutive odd integers\": x, (x+2), (x+4)
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\n" ); document.write( "\"3 times the sum of all three is 18 more than the product of the first and second integers\"
\n" ); document.write( "3(x + (x+2 + (x+4)) = x(x+2) + 18
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\n" ); document.write( "3(3x + 6) = x^2 + 2x + 18
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\n" ); document.write( "9x + 18 = x^2 + 2x + 18
\n" ); document.write( "Subtract 18 from both sides:
\n" ); document.write( "9x = x^2 + 2x
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\n" ); document.write( "0 = x^2 + 2x - 9x
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\n" ); document.write( "x^2 - 7x = 0
\n" ); document.write( "Factor out x
\n" ); document.write( "x(x - 7) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = 0
\n" ); document.write( "and
\n" ); document.write( "x = +7
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\n" ); document.write( "Both solutions will work in the original equation, however only x=7, 9, 11 are the odd solutions \n" ); document.write( "
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