document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197961>Question 197961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you asked three strangers about their birthdays, what is the probabilty..\r<BR>\n" );
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document.write( "a. All were born on Wednesday<BR>\n" );
document.write( "b. All were born on a different day of the week<BR>\n" );
document.write( "c. None were born on Saturday\r<BR>\n" );
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document.write( "Canm I get an explaination of how you got to the answer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148442 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "All Wednesdays:\r<BR>\n" );
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document.write( "There are seven different days in the week, so the probability that one person is born on a given day is <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{1}{7}\">.  Since each of the three birthdays is an independent event, the total probability is the product of the three individual probabilities:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{1}{7}\right)\left(\frac{1}{7}\right)\left(\frac{1}{7}\right)\">\r<BR>\n" );
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document.write( "Different day of the week:\r<BR>\n" );
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document.write( "The probability that the first guy is born on any one of the 7 days in the week is certainty, or 1.  The probability that the second guy was born on a different day is the number of days unused so far, or 6 divided by the number of possible days, or 7.  The probability that the third guy was born on yet a different day is calculated the same way, this time 5 divided by 7.  Again the total probability is the product:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 1\cdot\left(\frac{6}{7}\right)\left(\frac{5}{7}\right)\">\r<BR>\n" );
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document.write( "None on Saturday:\r<BR>\n" );
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document.write( "6 out of 7 ways <i>not</i> to be born on Saturday, so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{6}{7}\right)\left(\frac{6}{7}\right)\left(\frac{6}{7}\right)\">\r<BR>\n" );
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document.write( "By the way, you get to do your own arithmetic.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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