document.write( "Question 197961: If you asked three strangers about their birthdays, what is the probabilty..\r
\n" ); document.write( "\n" ); document.write( "a. All were born on Wednesday
\n" ); document.write( "b. All were born on a different day of the week
\n" ); document.write( "c. None were born on Saturday\r
\n" ); document.write( "\n" ); document.write( "Canm I get an explaination of how you got to the answer?
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Algebra.Com's Answer #148440 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
If you asked three strangers about their birthdays, what is the probabilty..
\n" ); document.write( "a. All were born on Wednesday
\n" ); document.write( "P(any one of them was born on Wednesday) = 1/7
\n" ); document.write( "P(all three were born on Wednesday) = (1/7)^3 = 1/343
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\n" ); document.write( "b. All were born on a different day of the week
\n" ); document.write( "P(all on different day) = 1 - [P(all on same day) + P(2 born on same day)]
\n" ); document.write( "----
\n" ); document.write( "P(all born on same day) = 7(1/343) = 1/7^2 = 1/49
\n" ); document.write( "P(2 born on same day) = 7(1/7)^2(6/7) = 0.12245
\n" ); document.write( "--
\n" ); document.write( "Therefore P(all on different day = 1-[(1/49) + 0.12245] = 0.857...
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\n" ); document.write( "c. None were born on Saturday
\n" ); document.write( "P(none born on Saturday) = (6/7)^3 = 0.6297...
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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