document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197923>Question 197923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are 220 barrels of cement in one shed and 510 barrels in another. How many barrels must be transferred from the second to the first shed will contain two thirds as much as the second? I need help setting up the equation...plez. thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148408 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 220 barrels of cement in one shed and 510 barrels in another. How many barrels must be transferred from the second to the first shed will contain two thirds as much as the second?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = number of barrels transferred<BR>\n" );
document.write( "then<BR>\n" );
document.write( "220 + x = (2/3)(510-x)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Now, solve for x:<BR>\n" );
document.write( "220 + x = (2/3)(510-x)<BR>\n" );
document.write( "Multiply both sides by 3:<BR>\n" );
document.write( "660 + 3x = (2)(510-x)<BR>\n" );
document.write( "660 + 3x = 1020 - 2x<BR>\n" );
document.write( "660 + 5x = 1020<BR>\n" );
document.write( "5x = 360<BR>\n" );
document.write( "x = 72 barrels\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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