document.write( "Question 197875: Leaving from her house, Mary leaves Pittsburgh in her car traveling towards Cleveland at 3PM. She travels at an average rate of 30 mi an hour. Mary's brother Jack leaves the house an hour later and follows the same route as Mary. He travels at an average rate of 60 mi. hr. How long will it take to catch up to Mary? \n" ); document.write( "
Algebra.Com's Answer #148384 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Leaving from her house, Mary leaves Pittsburgh in her car traveling towards Cleveland at 3PM. She travels at an average rate of 30 mi an hour. Mary's brother Jack leaves the house an hour later and follows the same route as Mary. He travels at an average rate of 60 mi. hr. How long will it take to catch up to Mary? \n" ); document.write( "------------------------------ \n" ); document.write( "Mary DATA: \n" ); document.write( "rate = 30 mph ; time = x hrs. ; distance = 30x miles \n" ); document.write( "---------------------------------------------- \n" ); document.write( "Jack DATA: \n" ); document.write( "rate = 60 mph ; time = x-1 hrs ; distance = 60(x-1) miles \n" ); document.write( "---------------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "distance = distance \n" ); document.write( "30x = 60x - 60 \n" ); document.write( "30x = 60 \n" ); document.write( "x = 2 hrs \n" ); document.write( "---- \n" ); document.write( "Mary will drive for x = 2 hrs \n" ); document.write( "Jack will crive for x-1 = 1 hr \n" ); document.write( "=================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |