document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197861>Question 197861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to use the change of base formula to solve 3^2x=15  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148379 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148379\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3^2x=15 <BR>\n" );
document.write( "---------<BR>\n" );
document.write( "To solve for x:<BR>\n" );
document.write( "log(3^2x) = log(15) common logs, base 10.  Natural logs would work too.<BR>\n" );
document.write( "2x*log(3) = log(15)<BR>\n" );
document.write( "2x = log(15)/log(3)<BR>\n" );
document.write( "x = log(15)/2log(3)<BR>\n" );
document.write( "x = log(15)/log(9)<BR>\n" );
document.write( "x = ~ 1.2325 </SPAN>\n" );
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