document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197854>Question 197854</A>: <I><SPAN STYLE=\"word-break: break-all;\">   Would you please help me with this question..\r<BR>\n" );
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document.write( "    In triangle ABC, AC = 18, BC =10, and cosC = 1/2. Find the area of triangle ABC to the nearest tenth of a square unit.\r<BR>\n" );
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document.write( "     Thanks!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148375 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148375\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Would you please help me with this question.. <BR>\n" );
document.write( "In triangle ABC, AC = 18, BC =10, and cosC = 1/2. Find the area of triangle ABC to the nearest tenth of a square unit. <BR>\n" );
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document.write( "Assuming the triangle is a right triangle, since cos(C) = 1/2,<BR>\n" );
document.write( "sin(C) = [sqrt(3)]/2<BR>\n" );
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document.write( "Formula:<BR>\n" );
document.write( "Area = (1/2)ab*sin(C)<BR>\n" );
document.write( "Area = (1/2)*10*18<BR>\n" );
document.write( "= 5*9*sqrt(3)<BR>\n" );
document.write( "= 77.94 sq. units<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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