document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197851>Question 197851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me to solve this equation (x+10)(2x-3)=54? I dont know how to solve it using quadratic equations. Thank you very much!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148353 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148353\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+10)(2x-3)=54<BR>\n" );
document.write( "2x^2+20x-3x-30=54<BR>\n" );
document.write( "2x^2+17x-30-54=0<BR>\n" );
document.write( "2x^2+17x-84=0<BR>\n" );
document.write( "(2x-7)(x+12)=0<BR>\n" );
document.write( "2x-7=0<BR>\n" );
document.write( "2x=7<BR>\n" );
document.write( "x=7/2<BR>\n" );
document.write( "x=3.5 ans.<BR>\n" );
document.write( "x+12=0<BR>\n" );
document.write( "x=-12 ans.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );