document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197733>Question 197733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation for the line that contains the point (4,-1) and is perpendicular to the equation y=2/3x + 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148349 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first we must find the slope of the equation y=(-2/3)x+7......since this is in point slope form....we can see the slope is -2/3.  now we know that any line perpendicular to this line will have a slope that is the negative reciprical of it.....the negative reciprical of -2/3 is 3/2<BR>\n" );
document.write( ":<BR>\n" );
document.write( "now we have the slope 3/2 and a point (4,-1)...using the point slope formula we have<BR>\n" );
document.write( ":<BR>\n" );
document.write( "y-(-1)=(3/2)(x-4)<BR>\n" );
document.write( ":<BR>\n" );
document.write( "y+1=(3/2)x-6 -->y=(3/2)x-7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );