document.write( "Question 197838: Junior's boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed fo the current?\r
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Algebra.Com's Answer #148333 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Going downstream, the speed of the current adds to the speed of the boat in still water, so if r represents the unknown speed of the current, the speed downstream is . Likewise, going upstream, the speed of the current subtracts from the speed in still water, so: \r
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\n" ); document.write( "\n" ); document.write( "Using the downstream trip is described by:\r
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\n" ); document.write( "\n" ); document.write( "And the upstream trip:\r
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\n" ); document.write( "\n" ); document.write( "Since the problem says both trips take the same amount of time, set the two fractions equal to each other and solve the proportion by cross-multiplying.\r
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