document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197795>Question 197795</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm not sure what I'm doing wrong in this problem. I got part of the problem but the other half it says it's incorrect can you help me\r<BR>\n" );
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document.write( "Find the domain of the function. If the domain can be specified by only one interval, use (NONE, NONE) for the second interval.\r<BR>\n" );
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document.write( "g(x) = sqrt(x)/(7 x^2 + 6 x - 1) \r<BR>\n" );
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document.write( "thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148319 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> g(x) = sqrt(x)/(7 x^2 + 6 x - 1) <BR>\n" );
document.write( "7x^2+6x-1<BR>\n" );
document.write( "=(7x^2+7x-x-1)<BR>\n" );
document.write( "=7x(x+1)-(x+1)<BR>\n" );
document.write( "=(7x-1)(x+1)<BR>\n" );
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document.write( "x cannot be less than zero because then the denominator would not be a real number.<BR>\n" );
document.write( "x cannot equal 1/7  because there would be a division by zero error.<BR>\n" );
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document.write( "x[0, 1/7)U(1/7, infinity)<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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