document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197737>Question 197737</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Please help me...Find to the nearest degree, all values of x in the interval 0<x<180 that satisfy<BR>\n" );
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document.write( " the equation 8cos^2x-2cosx - 1= 0. Thanks so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148268 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148268\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find to the nearest degree, all values of x in the interval 0 <BR>\n" );
document.write( "the equation 8cos^2x-2cosx - 1= 0<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(4cos(x)+1)(2cos(x)-1) = 0<BR>\n" );
document.write( "cos(x) = -1/4 or cos(x) = 1/2<BR>\n" );
document.write( "x = 104.48 degrees or x = -104.48 degrees<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x = 60 degrees or x = -60 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );