document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197714>Question 197714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given f(x)= 1/2x+1 and g(x) = &#8730;3x-5<BR>\n" );
document.write( "Determine (f.g)(x) and its domain.<BR>\n" );
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document.write( "Note:- the square root is on whole 3x-5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148259 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given f(x)= (1/2)x+1 and g(x) = &#8730;(3x-5)<BR>\n" );
document.write( "Determine (f.g)(x) and its domain.<BR>\n" );
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document.write( "f[g(x)] = f[sqrt(3x-5)] = (1/2)sqrt(3x+5) + 1<BR>\n" );
document.write( "Domain = ?<BR>\n" );
document.write( "3x+5 >= 0<BR>\n" );
document.write( "x >= -5/3<BR>\n" );
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document.write( "Domain of f[g(x)] is all Real Numbers >= -5/3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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