document.write( "Question 197676: I was given the following table
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document.write( "Input (x)--output(y)
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document.write( " 1--8
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document.write( " 2--14
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document.write( " 3--18
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document.write( " 4--24
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document.write( "I noticed that there was a pattern in the output with the numbers ending in either an 8 or a 4. I need a rule that explains the pattern. So far I have only come up with that when the input (x) is even, the rule is 5(x)+ 4. When the input (x) is odd, the rule is 5(x) + 3. I am not sure if this is correct or if there can be two different rules for one pattern. Is there a rule that fits every situation on this input/output chart? \n" );
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Algebra.Com's Answer #148228 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I was given the following table \n" ); document.write( "Input (x)--output(y) \n" ); document.write( "1--8 \n" ); document.write( "2--14 \n" ); document.write( "3--18 \n" ); document.write( "4--24 \n" ); document.write( "----------------- \n" ); document.write( "Using the point (1,8) and (4,24) \n" ); document.write( "slope = (24-8)/(4-1) = 16/3 \n" ); document.write( "--- \n" ); document.write( "intercept = ? \n" ); document.write( "8 = (16/3)*1 + b \n" ); document.write( "b = (24/3)-(16/3) \n" ); document.write( "b = 8/3 \n" ); document.write( "--- \n" ); document.write( "Equation: \n" ); document.write( "y = (16/3)x + (8/3) \n" ); document.write( "--------------------------- \n" ); document.write( "Another answer could be \n" ); document.write( "y = (2/3)x^3 -5x^2 + (49/3)X -4 \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |