document.write( "Question 197676: I was given the following table
\n" ); document.write( "Input (x)--output(y)
\n" ); document.write( " 1--8
\n" ); document.write( " 2--14
\n" ); document.write( " 3--18
\n" ); document.write( " 4--24
\n" ); document.write( "I noticed that there was a pattern in the output with the numbers ending in either an 8 or a 4. I need a rule that explains the pattern. So far I have only come up with that when the input (x) is even, the rule is 5(x)+ 4. When the input (x) is odd, the rule is 5(x) + 3. I am not sure if this is correct or if there can be two different rules for one pattern. Is there a rule that fits every situation on this input/output chart?
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Algebra.Com's Answer #148228 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I was given the following table
\n" ); document.write( "Input (x)--output(y)
\n" ); document.write( "1--8
\n" ); document.write( "2--14
\n" ); document.write( "3--18
\n" ); document.write( "4--24
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\n" ); document.write( "Using the point (1,8) and (4,24)
\n" ); document.write( "slope = (24-8)/(4-1) = 16/3
\n" ); document.write( "---
\n" ); document.write( "intercept = ?
\n" ); document.write( "8 = (16/3)*1 + b
\n" ); document.write( "b = (24/3)-(16/3)
\n" ); document.write( "b = 8/3
\n" ); document.write( "---
\n" ); document.write( "Equation:
\n" ); document.write( "y = (16/3)x + (8/3)
\n" ); document.write( "---------------------------
\n" ); document.write( "Another answer could be
\n" ); document.write( "y = (2/3)x^3 -5x^2 + (49/3)X -4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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