document.write( "Question 197653: a rectangular lawn is 80 ft by 60ft. part of the lawn is torn up to install a sidewalk of equal width around the lawn. The new area of the lawn is 800 ft^2. how wide is the sidewalk?\r
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document.write( "Hi - I can't figure this out. I know the area of the first rectangle is 4800 ft^2. Once I reduce the lawn I think the length is 40 ft and the length is 20 ft. That leaves 4000 ft of area. I don't konw how to find the width of the sidewalk. Thanks for your help.
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document.write( "This is not from a textbook but a worksheet my teacher gave us. \n" );
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Algebra.Com's Answer #148203 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a rectangular lawn is 80 ft by 60ft. part of the lawn is torn up to install a sidewalk of equal width around the lawn. The new area of the lawn is 800 ft^2. how wide is the sidewalk? \n" ); document.write( "-------------- \n" ); document.write( "Draw the picture of a rectangle inside a rectangle. \n" ); document.write( "The outer triangle is 80 by 60 = 4800 sq ft. \n" ); document.write( "----------------- \n" ); document.write( "Let the width of the sidewalk be \"x\" \n" ); document.write( "----------------- \n" ); document.write( "The inner rectangle has dimensions 80-2x and 60-2x \n" ); document.write( "The area of the inner rectangle is (80-2x)(60-2x) = 4800 -120x -160x + 4x^2 \n" ); document.write( "----------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "Area of the inner rectangle = 4x^2 - 280x +4800 = 800 sq. ft. \n" ); document.write( "Simplify and solve: \n" ); document.write( "x^2 - 70x + 1000 = 0 \n" ); document.write( "(x-20)(x-50) = 0 \n" ); document.write( "Realistic answer: \n" ); document.write( "x = 20 ft (width of the sidewalk) \n" ); document.write( " ---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |