document.write( "Question 3403: 35 coins consisting of dimes & nickles. value of coins is $3.30. How many of each type does he have?\r
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document.write( "How is this problem solved?
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document.write( "d+n= $3.30 \n" );
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Algebra.Com's Answer #1482 by drglass(89)![]() ![]() ![]() You can put this solution on YOUR website! If d is the number of dimes and n is the number of nickels, then \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "subtract n from both sides of the first equation to get \n" ); document.write( " \n" ); document.write( "Now reduce the equation: \n" ); document.write( " \n" ); document.write( "Subtract 3.5 from either side to get \n" ); document.write( "divide both sides by -0.05 to get n = 4. If we have 4 nickels, we must have 31 dimes (n + d = 35). 31 dimes is $3.10 and 4 nickels is $0.20, so the total amount is $3.30. \n" ); document.write( " |