document.write( "Question 3403: 35 coins consisting of dimes & nickles. value of coins is $3.30. How many of each type does he have?\r
\n" ); document.write( "\n" ); document.write( "How is this problem solved?
\n" ); document.write( "d+n= $3.30
\n" ); document.write( "

Algebra.Com's Answer #1482 by drglass(89)\"\" \"About 
You can put this solution on YOUR website!
If d is the number of dimes and n is the number of nickels, then

\n" ); document.write( "\"d+%2B+n+=+35\" and

\n" ); document.write( "\"0.1%2Ad+%2B+0.05%2An+=+3.3\"

\n" ); document.write( "subtract n from both sides of the first equation to get \"d+=+35+-+n\" and substitute d into the second equation.

\n" ); document.write( "\"0.1%2A%2835+-+n%29+%2B+0.05%2An+=+3.3\"

\n" ); document.write( "Now reduce the equation:

\n" ); document.write( "\"0.1%2A%2835+-+n%29+%2B+0.05%2An+=+3.5+-+0.1%2An+%2B+0.05%2An+=+3.5+-+0.05n\"

\n" ); document.write( "Subtract 3.5 from either side to get \"-0.05n+=+-0.2\"

\n" ); document.write( "divide both sides by -0.05 to get n = 4. If we have 4 nickels, we must have 31 dimes (n + d = 35). 31 dimes is $3.10 and 4 nickels is $0.20, so the total amount is $3.30.
\n" ); document.write( "
\n" );