document.write( "Question 197634: factor out the problem.
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\n" ); document.write( "2x^2+13x+15
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Algebra.Com's Answer #148195 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Looking at the expression $\"2x%5E2%2B13x%2B15\"$ , we can see that the first coefficient is $\"2\"$ , the second coefficient is $\"13\"$ , and the last term is $\"15\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient $\"2\"$ by the last term $\"15\"$ to get $\"%282%29%2815%29=30\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to $\"30\"$ (the previous product) and add to the second coefficient $\"13\"$ ?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of $\"30\"$ (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of $\"30\"$ :\r
\n" ); document.write( "\n" ); document.write( "1,2,3,5,6,10,15,30\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-5,-6,-10,-15,-30\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to $\"30\"$ .\r
\n" ); document.write( "\n" ); document.write( "1*30
\n" ); document.write( "2*15
\n" ); document.write( "3*10
\n" ); document.write( "5*6
\n" ); document.write( "(-1)*(-30)
\n" ); document.write( "(-2)*(-15)
\n" ); document.write( "(-3)*(-10)
\n" ); document.write( "(-5)*(-6)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient $\"13\"$ :\r
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First Number	Second Number	Sum
1	30	1+30=31
2	15	2+15=17
3	10	3+10=13
5	6	5+6=11
-1	-30	-1+(-30)=-31
-2	-15	-2+(-15)=-17
-3	-10	-3+(-10)=-13
-5	-6	-5+(-6)=-11

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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers $\"3\"$ and $\"10\"$ add to $\"13\"$ (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers $\"3\"$ and $\"10\"$ both multiply to $\"30\"$ and add to $\"13\"$ \r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term $\"13x\"$ with $\"3x%2B10x\"$ . Remember, $\"3\"$ and $\"10\"$ add to $\"13\"$ . So this shows us that $\"3x%2B10x=13x\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"2x%5E2%2Bhighlight%283x%2B10x%29%2B15\"$ Replace the second term $\"13x\"$ with $\"3x%2B10x\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"%282x%5E2%2B3x%29%2B%2810x%2B15%29\"$ Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( " $\"x%282x%2B3%29%2B%2810x%2B15%29\"$ Factor out the GCF $\"x\"$ from the first group.\r
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\n" ); document.write( "\n" ); document.write( " $\"x%282x%2B3%29%2B5%282x%2B3%29\"$ Factor out $\"5\"$ from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x%2B5%29%282x%2B3%29\"$ Combine like terms. Or factor out the common term $\"2x%2B3\"$ \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So $\"2x%5E2%2B13x%2B15\"$ factors to $\"%28x%2B5%29%282x%2B3%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by FOILing $\"%28x%2B5%29%282x%2B3%29\"$ to get $\"2x%5E2%2B13x%2B15\"$ or by graphing the original expression and the answer (the two graphs should be identical).
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