document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197618>Question 197618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A diameter of a circle has endpoints at (-1,3) and (-1,-3) Find the area of the circle and please also graph it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #148189 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=148189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the given coordinates of the end points of the diameter, (-1,3) and (-1,-3), you can see that the diameter is 6 units.<BR>\n" );
document.write( "This was found by:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D+=+y%5B2%5D-y%5B1%5D ALIGN=MIDDLE  ALT=\"D+=+y%5B2%5D-y%5B1%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substituting <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5B1%5D+=+3 ALIGN=MIDDLE  ALT=\"y%5B1%5D+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5B2%5D+=+-3 ALIGN=MIDDLE  ALT=\"y%5B2%5D+=+-3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, we get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D+=+-3-3 ALIGN=MIDDLE  ALT=\"D+=+-3-3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D+=+6 ALIGN=MIDDLE  ALT=\"D+=+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > so the radius, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+3 ALIGN=MIDDLE  ALT=\"r+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The area of a circle is found by:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"A+=+pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substituting <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi+=+3.14 ALIGN=MIDDLE  ALT=\"pi+=+3.14\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+3 ALIGN=MIDDLE  ALT=\"r+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > we get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%283.14%29%283%5E2%29 ALIGN=MIDDLE  ALT=\"A+=+%283.14%29%283%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%283.14%29%289%29 ALIGN=MIDDLE  ALT=\"A+=+%283.14%29%289%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28A+=+28.26%29 ALIGN=MIDDLE  ALT=\"highlight%28A+=+28.26%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >sq. units.<BR>\n" );
document.write( "To graph the circle, you first need to find the equation of the circle.<BR>\n" );
document.write( "Using the standard form for a circle with center at (h,k) and radius r:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 ALIGN=MIDDLE  ALT=\"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substitute r = 3.<BR>\n" );
document.write( "The center of this circle is located at (-1, 0), so making the appropriate substitutions, we get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-%28-1%29%29%5E2%2B%28y-0%29+=+3%5E2 ALIGN=MIDDLE  ALT=\"%28x-%28-1%29%29%5E2%2B%28y-0%29+=+3%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplifying, we have:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B1%29%5E2%2B%28y%29%5E2+=+9 ALIGN=MIDDLE  ALT=\"%28x%2B1%29%5E2%2B%28y%29%5E2+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now to graph this circle, you have to solve this equation for y and then graph the two solutions  on the same coordinate plane.<BR>\n" );
document.write( "Solving for y:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B1%29%5E2%2By%5E2+=+9 ALIGN=MIDDLE  ALT=\"%28x%2B1%29%5E2%2By%5E2+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B1%29%5E2 ALIGN=MIDDLE  ALT=\"%28x%2B1%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2+=+-%28x%2B1%29%5E2%2B9 ALIGN=MIDDLE  ALT=\"y%5E2+=+-%28x%2B1%29%5E2%2B9\"   DISABLED_style= \"max-width:90%; height:auto;\" > Expand the right side.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2+=+-%28x%5E2%2B2x%2B1%29%2B9 ALIGN=MIDDLE  ALT=\"y%5E2+=+-%28x%5E2%2B2x%2B1%29%2B9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2+=+-x%5E2-2x%2B8 ALIGN=MIDDLE  ALT=\"y%5E2+=+-x%5E2-2x%2B8\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now take the square root of both sides to get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+sqrt%28-x%5E2-2x%2B8%29 ALIGN=MIDDLE  ALT=\"y+=+sqrt%28-x%5E2-2x%2B8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-sqrt%28-x%5E2-2x%2B8%29 ALIGN=MIDDLE  ALT=\"y+=+-sqrt%28-x%5E2-2x%2B8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now we can graph these two solutions:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28400%2C400%2C-5%2C5%2C-5%2C5%2Csqrt%28-x%5E2-2x%2B8%29%2C-sqrt%28-x%5E2-2x%2B8%29%29 ALIGN=MIDDLE  ALT=\"graph%28400%2C400%2C-5%2C5%2C-5%2C5%2Csqrt%28-x%5E2-2x%2B8%29%2C-sqrt%28-x%5E2-2x%2B8%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );