document.write( "Question 197509: Please help with the following question Write the equation for a line that is perpendicular to the line, y=3x+10/3 and goes thru the point [-15,6] \n" ); document.write( "
Algebra.Com's Answer #148169 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Please help with the following question Write the equation for a line that is perpendicular to the line, y=3x+10/3 and goes thru the point [-15,6]
\n" ); document.write( ".
\n" ); document.write( "The slope of (from inspection)
\n" ); document.write( "y=3x+10/3
\n" ); document.write( "is 3
\n" ); document.write( ".
\n" ); document.write( "If a line is to be perpendicular the slope has to be the \"negative reciprocal\":
\n" ); document.write( "Let m = our new slope
\n" ); document.write( "then
\n" ); document.write( "3m = -1
\n" ); document.write( "m = -1/3 (our new slope)
\n" ); document.write( ".
\n" ); document.write( "Using our new slope and [-15,6]
\n" ); document.write( "plug it into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - 6 = (-1/3)(x - (-15))
\n" ); document.write( "y - 6 = (-1/3)(x + 15)
\n" ); document.write( "y - 6 = (-1/3)x - 5
\n" ); document.write( "y = (-1/3)x + 1 (this is what they're looking for)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );