document.write( "Question 197358: In 1994, the life expectancy of males in a certain country was 69.6 years. In 1998, it was 73.0 years. Let E represent the life expectancy in year t and let t represent the number of years since 1994.
\n" ); document.write( "E(t)=_t+_\r
\n" ); document.write( "\n" ); document.write( "Use the function to predict the life expectancy of males in 2008
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Algebra.Com's Answer #148155 by ankor@dixie-net.com(22740)\"\" \"About 
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In 1994, the life expectancy of males in a certain country was 69.6 years.
\n" ); document.write( " In 1998, it was 73.0 years. Let E represent the life expectancy in year t
\n" ); document.write( " and let t represent the number of years since 1994.
\n" ); document.write( ":
\n" ); document.write( "Find the slope
\n" ); document.write( "In 1994; x1=0 and y1=69.6
\n" ); document.write( "In 1998; x2=4 and y2=73
\n" ); document.write( ":
\n" ); document.write( "Find the slope (m) using the slope equation: m = \"%28y2-y1%29%2F%28x2-x1%29\"
\n" ); document.write( "m = \"%2873-69.6%29%2F%284+-+0%29%29\" = \"%283.4%29%2F%284%29\" = .85
\n" ); document.write( ":
\n" ); document.write( "Use the point/slope formula to write the equation; y - y1 = m(x - x1)
\n" ); document.write( "y - 69.6 = .85(x - 0)
\n" ); document.write( "y = .85x + 69.6
\n" ); document.write( ":
\n" ); document.write( "therefore:
\n" ); document.write( "The Linear function E(t) that fits the data is.
\n" ); document.write( "E(t)= .85t + 69.6
\n" ); document.write( ":
\n" ); document.write( "Use the Function to predict the life expectancy of males in 2008.
\n" ); document.write( "This means t=14; substitute 14 for t in the equation
\n" ); document.write( "E(14)= .85(14) + 69.6
\n" ); document.write( "E(14)= 11.9 + 69.6
\n" ); document.write( "E(14)= 81.5 yrs is the life expectancy in 2008\r
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