document.write( "Question 197519: Dawns Suv gets 17 miles per gallon (mpg) in city driving and 23 mpg in highway driving. The suv is driven 290 miles on 15 gallons of gas. How many miles were dricen in the city and how many miles were driven on the highway? \n" ); document.write( "
Algebra.Com's Answer #148147 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Suv gets 17 miles per gallon (mpg) in city driving and 23 mpg in highway driving. \n" ); document.write( "The suv is driven 290 miles on 15 gallons of gas. \n" ); document.write( " How many miles were driven in the city and how many miles were driven on the highway \n" ); document.write( ": \n" ); document.write( "Let c = no. of miles driven in the city \n" ); document.write( "Let h = no. of miles drive on the highway \n" ); document.write( ": \n" ); document.write( "c + h = 290 \n" ); document.write( "h = (290-c) \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "multiply equation by 17*23 = 391, results: \n" ); document.write( "23c + 17h = 391(15) \n" ); document.write( ": \n" ); document.write( "23c + 17h = 5865 \n" ); document.write( ": \n" ); document.write( "substitute (290-c) for h: \n" ); document.write( "23c + 17(290-c) = 5865 \n" ); document.write( ": \n" ); document.write( "23c + 4930 - 17c = 5865 \n" ); document.write( ": \n" ); document.write( "23c - 17c = 5865 - 4930 \n" ); document.write( ": \n" ); document.write( "6c = 935 \n" ); document.write( "c = \n" ); document.write( "c = 155.8 mi in city \n" ); document.write( "and \n" ); document.write( "h = 290 - 155.8 \n" ); document.write( "h = 134.2 mi on the highway \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution on calc; enter: \n" ); document.write( " |