document.write( "Question 27252: 3 square root a-2= square root 8a+1 \n" ); document.write( "
Algebra.Com's Answer #14812 by bmauger(101)\"\" \"About 
You can put this solution on YOUR website!
I'm going to assume you mean \"3sqrt%28a-2%29=sqrt%288a%2B1%29\" If you meant \"3sqrt%28a%29-2=sqrt%288a%29%2B1\" or something else then you'll have to try asking again.\r
\n" ); document.write( "\n" ); document.write( "You want to first square both sides (the inverse equation of squaring...) This gives us: \r
\n" ); document.write( "\n" ); document.write( "\"9%28a-2%29=%288a%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "Now we can distribute on the right:\r
\n" ); document.write( "\n" ); document.write( "\"9a-18=8a%2B1\"\r
\n" ); document.write( "\n" ); document.write( "Rearranging gives us:\r
\n" ); document.write( "\n" ); document.write( "\"a=19\"\r
\n" ); document.write( "\n" ); document.write( "Double checking:\r
\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%28a-2%29=sqrt%288a%2B1%29\"
\n" ); document.write( "\"3%2Asqrt%2819-2%29=sqrt%288%2A19%2B1%29\"
\n" ); document.write( "\"3sqrt%2817%29=sqrt%28153%29\"
\n" ); document.write( "\"3sqrt%2817%29=sqrt%289%2A17%29\"
\n" ); document.write( "\"3sqrt%2817%29=3sqrt%2817%29\" Check.
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