document.write( "Question 197408: Lan leaves Avon at noon biking to Batavia at 16 km/h at 1pm. Joey leaves Batavia abd bikes toward Avon at 20 km/h. If the distance between Avon and Batavia is 70 km, at what time do Lan and Joey meet? \n" ); document.write( "
Algebra.Com's Answer #148033 by ankor@dixie-net.com(22740)\"\" \"About 
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Lan leaves Avon at noon biking to Batavia at 16 km/h
\n" ); document.write( "At 1pm, Joey leaves Batavia abd bikes toward Avon at 20 km/h.
\n" ); document.write( "If the distance between Avon and Batavia is 70 km, at what time do Lan and Joey meet?
\n" ); document.write( ":
\n" ); document.write( "Let t = L's travel time (leaves at noon)
\n" ); document.write( "then
\n" ); document.write( "(t-1) = J's travel time (leaves at 1 PM)
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\n" ); document.write( "When the two meet, they will have traveled a total of 70 km.
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\n" ); document.write( "Write a distance equation: dist = speed * time
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\n" ); document.write( "L's dist + J's dist = 70 km
\n" ); document.write( "16t + 20(t-1) = 70
\n" ); document.write( ":
\n" ); document.write( "16t + 20t - 20 = 70
\n" ); document.write( ":
\n" ); document.write( "36t = 70 + 20
\n" ); document.write( "t = \"90%2F36\"
\n" ); document.write( "t = 2.5 hrs which is 2 hr 30 min
\n" ); document.write( "therefore
\n" ); document.write( "they will meet a 2:30 PM
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\n" ); document.write( "Check solution, find the distance of each
\n" ); document.write( "2.5*16 = 40
\n" ); document.write( "1.5*20 = 30
\n" ); document.write( "-----------
\n" ); document.write( "total = 70 km \n" ); document.write( "
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