document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27219>Question 27219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much pure salt must be added to to 25 grams of a 12% salt solution to make it a 20% solution.  I am having a very hard time trying to figure this problem out.  Thanks for your help.\r<BR>\n" );
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document.write( "Dennis </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14802 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 25(12)=20(x+25)<BR>\n" );
document.write( "300=20x+500<BR>\n" );
document.write( "20x=200<BR>\n" );
document.write( "x=10\r<BR>\n" );
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document.write( "Hence, about 10grams is needed.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
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