document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27200>Question 27200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -3(x+2)-2=6(2x-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14797 by </B><A HREF=/tutors/aboutme.mpl?userid=JayJay_T><B>JayJay_T(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JayJay_T><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3(x+2)-2=6(2x-1)\r<BR>\n" );
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document.write( "=> -3x-6-2=12x-6 (you can loose the '-6' since it's at both sides of the equation)<BR>\n" );
document.write( "=> -3x-2=12x<BR>\n" );
document.write( "=> -3x-12x=2<BR>\n" );
document.write( "=> -15x=2<BR>\n" );
document.write( "=> x=-2/15 </SPAN>\n" );
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